Derive An Expression For Electric Field Intensity Due To A Short Electric Dipole At Any Point Situated Along The Line Of Its Axis (2023)

FAQs

What is the expression for the electric potential due to a short dipole at any point? ›

Therefore, the electric potential due to an electric dipole at a given point is equal to KPcosθr2−a2cos2θ. Special cases: (i) When the given point is on the axial line of the dipole (i.e. θ=0).

Hence final answer is EA=p4πϵox3.

⟹ EA=4πϵrP.

Electric field intensity due to an electric dipole varies with distance (r) as E∝rn, where n is.

The electric potential due to a dipole at its axial point is zero.

The electric potential due to a dipole at its equatorial point is zero.

Electric field intensity = Force/Charge In symbol its form, this can be represented as: E = F/q Let us derive a unit for electric field intensity. The formula of electric intensity is the ratio of force and charge. The standard unit of Force is Newton and the charge is generally measured in Coulomb.

Electric field intensity is the strength of an electric field at any point. It is equal to the electric force per unit charge experienced by a test charge placed at that point, or E=qF.

According to it, if we introduce a new charge in this region, that charge will experience some force due to the electric field produced by the previous charges. We can determine or calculate the magnitude of the charge of an electric field by the formula E= k q/d².

According to the electric field due to dipole definition, the field strength due to dipole is always directly proportional to the dipole moment. Moreover, it is inversely proportional to the cube of the distance of separation.

What is electric field due to dipole? ›

The electric field strength due to a dipole, far away, is always proportional to the dipole moment and inversely proportional to the cube of the distance. Dipole moment is the product of the charge and distance between the two charges.

For the dependency of electric potential (V) with distance (r) can be clearly seen by the given formula. Thus, the electric dipole varies inversely to the square of a distance ${{(r)}}$.

Electric intensity due to an electric dipole varies with distance r as E alpha r^n , where 'n' is.

Electric field due to isolated point charge varies inversely with square of the distance but electric field due to dipole varies inversely with cube of the distance.

The electric field intensity is related to distance as : E = (1/4 π ∈ )p/r³ ; So Electric field magnitude decreases with the inverse cube of the distance from the dipole to the observation location.