## 1. Derive an expression for electric field due to an electric dipole at a point ...

Electric field due to an electric dipole at a point on its axial line: AB is an electric dipole of two point charges −q and +q separated by small distance 2d.

Click here👆to get an answer to your question ✍️ Derive an expression for electric field due to an electric dipole at a point on its axial line.

## 2. [Punjabi] Find an expression for electric intensity due to a short ele

Posted: Jul 21, 2023

Find an expression for electric intensity due to a short electric dipole at any point situated along a line inclined at an angle from the dipole axis.

## 3. Derive an expression for the intensity of the electric field at a point ... - Toppr

Missing: short | Show results with:short

Click here👆to get an answer to your question ✍️ Derive an expression for the intensity of the electric field at a point on the axial line of an electric dipole.

## 4. Electric Field Intensity at any point due to an Ideal Dipole - BYJU'S

An electric dipole is defined as a pair of opposite charges q and –q separated by a distance d. Derivation of Electric Field Intensity for points on the Axial ...

The electric field intensity at a point is the force experienced by a unit positive charge placed at that point. The electric field intensity of a dipole can be derived by considering two charge system.

## 5. Electric Field at any point due to an Electric Dipole || in HINDI for Class 12

Duration: 25:24Posted: Apr 7, 2017

In this Physics video lecture in Hindi for class 12 we derived the the electric field intensity at any point due to an electric dipole. To find the equation ...

## 6. Derive an expression for electric field intensity due to an electric dipole at ...

Hint: To derive the expression for electric field due to an electric dipole, consider AB is an electric dipole of two point charges – q and + q separated by ...

Derive an expression for electric field intensity due to an electric dipole at a point on its axial line.. Ans: Hint:To derive the expression for electric field due to an electric dipole, consider AB is an electric dipole of two point charges – q an...

## 7. Electric Dipole and Derivation of Electric field intensity at different ...

Jan 5, 2023 · Let a point P be on the axis of an electric dipole and place it at a distance r from the center point O of the electric dipole. Now put the test ...

Electric Dipole, Electric dipole moment and Derivation of Electric field intensity at different points of an electric dipole

## 8. Explain Electric field intensity at any point due to a short Electric dipole?

It is along AB vector. The center of dipole is O. Now we have to find electric field intensity at point k. According to the above mentioned data. OK=r

Here short dipole is represented by AB. The moment of dipole is denoted by It is along AB vector. The center of dipole is O. Now we have to find electric field intensity at point k. According to the above mentioned data. OK=r can be divided into two rectangular parts:

## FAQs

### What is the expression for the electric potential due to a short dipole at any point? ›

Therefore, the electric potential due to an electric dipole at a given point is equal to **KPcosθr2−a2cos2θ**. Special cases: (i) When the given point is on the axial line of the dipole (i.e. θ=0).

**What is the derive expression for electric field intensity due to electric dipole at any point equatorial line? ›**

Hence final answer is **EA=p4πϵox3**.

**What is the expression for electric field intensity at any point of dipole? ›**

⟹ **EA=4πϵrP**.

**What is the electric field intensity due to an electric dipole at a point at distance r from its centre varies as? ›**

Electric field intensity due to an electric dipole varies with distance (r) as E∝rn, where n is.

**What is the electric potential due to a dipole on its axial point? ›**

The electric potential due to a dipole at its axial point is **zero**.

**What is the electric potential due to a short electric dipole of dipole moment P at an equatorial point? ›**

The electric potential due to a dipole at its equatorial point is **zero**.

**What is the formula for electric field intensity? ›**

Electric field intensity = Force/Charge In symbol its form, this can be represented as: **E = F/q** Let us derive a unit for electric field intensity. The formula of electric intensity is the ratio of force and charge. The standard unit of Force is Newton and the charge is generally measured in Coulomb.

**What is electric field intensity and derive its expression? ›**

Electric field intensity is the strength of an electric field at any point. It is equal to the electric force per unit charge experienced by a test charge placed at that point, or **E=qF**.

**How do you derive an expression of electric field due to a point charge? ›**

According to it, if we introduce a new charge in this region, that charge will experience some force due to the electric field produced by the previous charges. We can determine or calculate the magnitude of the charge of an electric field by the formula **E= k q/d ^{2}**.

**What is the electric field intensity due to a short dipole remains directly proportional to? ›**

According to the electric field due to dipole definition, the field strength due to dipole is always directly proportional to the **dipole moment**. Moreover, it is inversely proportional to the cube of the distance of separation.

### What is electric field due to dipole? ›

The electric field strength due to a dipole, far away, is **always proportional to the dipole moment and inversely proportional to the cube of the distance**. Dipole moment is the product of the charge and distance between the two charges.

**How does the electric field of an electric dipole vary with distance? ›**

For the dependency of electric potential (V) with distance (r) can be clearly seen by the given formula. Thus, the electric dipole varies **inversely to the square of a distance** ${{(r)}}$.

**What is the electric intensity due to a short electric dipole varies with distance? ›**

Electric intensity due to an electric dipole varies with distance r as **E alpha r^n** , where 'n' is.

**How does electric field intensity vary with distance r due to a point charge? ›**

Electric field due to isolated point charge varies **inversely with square of the distance** but electric field due to dipole varies inversely with cube of the distance.

**How does the electric field intensity change with distance from a dipole? ›**

The electric field intensity is related to distance as : E = (1/4 π ∈ )p/r^{3} ; So **Electric field magnitude decreases with the inverse cube of the distance from the dipole to the observation location**.